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quadcore
@quadcore
July 2022
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(8sin^2x-6sinx-5)*[tex] \sqrt{-cosx} [/tex]=0
Желательно подробно , зарание спасибо.
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sedinalana
Verified answer
ОДЗ
cosx≤0⇒x∈[π/2+2πn;3π/2+2πn,n∈z]
8sin²x-6sinx-5=0
sinx=a
8a²-6a-5=0
D=36+160=196
a1=(6-14)/16=-1/2⇒sinx=-1/2
x=7π/6+2πn (с учетом ОДЗ)
a2=(6+14)/16=1,25⇒sinx=1,25>1 нет решения
cosx=0
x=π/2+πn,n∈z
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Answers & Comments
Verified answer
ОДЗcosx≤0⇒x∈[π/2+2πn;3π/2+2πn,n∈z]
8sin²x-6sinx-5=0
sinx=a
8a²-6a-5=0
D=36+160=196
a1=(6-14)/16=-1/2⇒sinx=-1/2
x=7π/6+2πn (с учетом ОДЗ)
a2=(6+14)/16=1,25⇒sinx=1,25>1 нет решения
cosx=0
x=π/2+πn,n∈z