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Ilyasssssss
@Ilyasssssss
July 2022
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[tex]p= log_{1,4} 3
( 7^{2p}- 5^{2p})/( 7^{2p}+2* 7^{p}* 5^{p}+ 5^{2p})=?[/tex]
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mmb1
Verified answer
Обозначим 7^p=a
5^p=b
a/b = (7/5)^p = (7/5) ^ log 1.4 3 = 3
a b > 0
7/5=1.4
(a²-b²)/(a²+2ab+b²) = (a-b)(a+b) /(a+b)² = (a-b)/(a+b) = делим числитель и знаменатель на b = (a/b - 1)/(a/b + 1) = (3-1)/(3+1)=2/4=1/2
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Answers & Comments
Verified answer
Обозначим 7^p=a5^p=b
a/b = (7/5)^p = (7/5) ^ log 1.4 3 = 3
a b > 0
7/5=1.4
(a²-b²)/(a²+2ab+b²) = (a-b)(a+b) /(a+b)² = (a-b)/(a+b) = делим числитель и знаменатель на b = (a/b - 1)/(a/b + 1) = (3-1)/(3+1)=2/4=1/2