решите неравенства
[tex] \frac{(4x-3) ^{2} }{7 x^{2} +3} \geq \frac{ x^{2} }{7 x^{2} +3} [/tex]
[tex] \frac{3x-2}{4 x^{2} +9} \leq \frac{3x-2}{4 x^{2} +5} [/tex]
[tex] \frac{4}{ x^{2} -4x} \leq \frac{1}{x-4} [/tex]
[tex] \frac{(4x-3) ^{2} }{7 x^{2} +3} \geq \frac{ x^{2} }{7 x^{2} +3} [/tex]
[tex] \frac{3x-2}{4 x^{2} +9} \leq \frac{3x-2}{4 x^{2} +5} [/tex]
[tex] \frac{4}{ x^{2} -4x} \leq \frac{1}{x-4} [/tex]
More Questions From This User See All
Answers & Comments
(4x-3)²/ (7x²+3) - x²/(7x²+3) ≥0
(15x²-24x+9)(7x²+3)≥0
x=1; x=3/5;
otvet:x∈(-∞;3/5]∪[1; +∞)
3)4/(x²-4x)≤1/(x-4)
4/(x(x-4)) - 1/(x-4)
(4-x)/(x(x-4))
(4-x)(x(x-4))≤0
x≥4; x≤0; x≤4
otvet: x∈[0;4]∪[4;+∞)
2) (3x-2)/ (4x²+9) ≤ (3x-2)/(4x²+5)
(3x-2)[4x²+5- 4x²-9]/ (4x²+9)(4x²+5)
(8-12x)(4x²+9)(4x²+5)≤0
x≥2/3;
otvet:x∈[2/3;+∞)