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Support001
@Support001
August 2022
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[tex]6^x+9^x=2^{2x+1}[/tex]
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thumbelina06
разделим на
пусть
= t причем t строго больше нуля
D=1+8=9
t=(-1+3)\-4=-1\2 не подходит
t=(-1-3)\-4=1
вернемся к х
x=0
Ответ:0
1 votes
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Answers & Comments
пусть = t причем t строго больше нуля
D=1+8=9
t=(-1+3)\-4=-1\2 не подходит
t=(-1-3)\-4=1
вернемся к х
x=0
Ответ:0