[tex]sin \alpha =- \frac{4}{5}, \pi \leq \alpha \leq \frac{3 \pi }{2} [/tex]. Created by irinaberger. algebra-ru

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[tex]sin \alpha =- \frac{4}{5}, \pi \leq \alpha \leq \frac{3 \pi }{2} [/tex]

кувшининка $\pi$
значит $cos a0; ctg a>0;$
$sin^2 a+cos^2 a=1$
$cos a=-\sqrt{1-sin^2 a}=-\sqrt{1-(-\frac{4}{5})^2}=-\frac{3}{5}$
$tg a=\frac{sin a}{cos a}=\frac{-\frac{4}{5}}{-\frac{3}{5}}=\frac{4}{3}$
$ctg a=\frac{1}{ctg a}=\frac{1}{\frac{4}{3}}=\frac{3}{4}$

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Там нужно на отрезке решение найти наверное

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