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irinaberger
@irinaberger
July 2022
2
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решите уравнение)
[tex]3sin ^{2} x+4sinxcosx-3=0[/tex]
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Answers & Comments
prostomama1
4sinxcosx-3cos^2x=0
cosx(4sinx-3cosx)=0
cosx=0
x=пи/2+пиK
4sinx=3cosx
tgx=3/4
x=arctg3/4+пиK
1 votes
Thanks 1
mmb1
Verified answer
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0 votes
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Answers & Comments
4sinxcosx-3cos^2x=0
cosx(4sinx-3cosx)=0
cosx=0
x=пи/2+пиK
4sinx=3cosx
tgx=3/4
x=arctg3/4+пиK
Verified answer
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