Решите уравнение [tex] \frac{3}{x+2} - \frac{2x-1}{x+1} = \frac{2x+2}{ x^{2} +3x+2} [/tex]. Created by sweetescape. algebra-ru

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August 2022 1 18 Report

Решите уравнение
[tex] \frac{3}{x+2} - \frac{2x-1}{x+1} = \frac{2x+2}{ x^{2} +3x+2} [/tex]

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LEROU21 $\frac{3}{x+2} - \frac{2x-1}{x+1} = \frac{2x+2}{ x^{2} +3x+2}$
$3(x+1)-(x+2)(2x-1)=2x+2$
$5-2 x^{2} =2x+2$
$-2 x^{2} -2x+3=0$
$x^{2} +x- \frac{3}{2} =0$
$x^{2} +x= \frac{3}{2}$
$x^{2} +x+ \frac{1}{4} = \frac{7}{4}$
$(x+ \frac{1}{2} )^2= \frac{7}{4}$
$x+ \frac{1}{2} = \frac{ \sqrt{7} }{2}$ или
$x+ \frac{1}{2} =- \frac{ \sqrt{7} }{2}$
$x= - \frac{1}{2} - \frac{ \sqrt{7} }{2}$

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legkovaya mashina vyehala na 2 minut pozdnee gruzovoj i dognala gruzovuyu cherez 10ca609db1f67c12fd77c950ca6ead0777 14577

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