tex]...

BorisTitanov47 @BorisTitanov47

July 2022 1 2 Report

#1 Составьте квадратное уравнение, корни которого равны
[tex] - \frac{1}{2} [/tex]
и
[tex] \frac{1}{5} [/tex]

Answers & Comments

rs19990809

Ответ:

${x}^{2} + 0.3x - 0.1 = 0$

Объяснение:

$x1 \times x2 = c \\ x1 + x2 = - b\\ \frac{1}{5} \times ( - \frac{1}{2}) = - 0.1 \\ \frac{1}{5} - \frac{1}{2} = - 0.3 \\ c = - 0.1 \\ b = 0.3 \\ {x}^{2} + bx + c = 0 \\ {x}^{2} + 0.3x - 0.1 = 0$

Составили приведенное квадратное уравнение по теореме Виета

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