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Yamamiwhami
@Yamamiwhami
July 2022
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Решить уравнения:[tex] \sqrt{17- x^{2} } |2-x|= (x^{2} -14) \sqrt{17- x^{2} } \\ |x-10|| x^{2} -x-3|=(x-10)(3-2x)[/tex]
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sangers1959
Verified answer
√(17-x²)*I2-xI=(x²-14)*√(17-x²) ОДЗ: 17-х²≥0 х∈[-√17;√17]
√(17-х²)=0 17-х²=0 х=+/-√17
I2-xI=x²-14
x<2 2-x=x²-14 x²+x-16=0 D=65 x₁≈-4,53 х₁∉ по ОДЗ x₂≈3,53 x₂∉
x>2 -2+x=x²-14 x²-x-12=0 D=49 x₃=4 x₄=-3 x₄∉
Ответ: х₁=4, х₂=√17, х₃=-√17.
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Yamamiwhami
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Verified answer
√(17-x²)*I2-xI=(x²-14)*√(17-x²) ОДЗ: 17-х²≥0 х∈[-√17;√17]√(17-х²)=0 17-х²=0 х=+/-√17
I2-xI=x²-14
x<2 2-x=x²-14 x²+x-16=0 D=65 x₁≈-4,53 х₁∉ по ОДЗ x₂≈3,53 x₂∉
x>2 -2+x=x²-14 x²-x-12=0 D=49 x₃=4 x₄=-3 x₄∉
Ответ: х₁=4, х₂=√17, х₃=-√17.