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Saires777
@Saires777
July 2022
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1) Решить показательное неравенство.
[tex] 3^{x+3} -3^{x} \ \textgreater \ 78[/tex]
2) Решить неравенство.
[tex]log_3(x^2+x)=0[/tex]
3) Вычислить.
sin 2x, tg 2x если х принадлежит 1й четверти, [tex]sin x\frac{3}{5} [/tex]
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sedinalana
Verified answer
1
3^x*(27-1)>78
26*3^x>78
3^x>3
x>1
x∈(1;∞)
2
ОДЗ
x²+x>0
x(x+1)>0
x=1 x=-1
x∈(-∞;-1) U (0;∞)
x²+x=1
x²+x-1=0
D=1+4=5
x1=(-1-√5)/2 U x2=(-1+√5)/2
3
sinx=3/5
cosx=√(1-sin²x)=√(1-9/25)=√16/25=4/5
sin2x=2sinx*cosx=2*3/5*4/5=24/25
cos2x=cos²x-sin²x=16/25-9/25=7/25
tg2x=sin2x/cos2x=24/25:7/25=24/25*25/7=24/7
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Answers & Comments
Verified answer
13^x*(27-1)>78
26*3^x>78
3^x>3
x>1
x∈(1;∞)
2
ОДЗ
x²+x>0
x(x+1)>0
x=1 x=-1
x∈(-∞;-1) U (0;∞)
x²+x=1
x²+x-1=0
D=1+4=5
x1=(-1-√5)/2 U x2=(-1+√5)/2
3
sinx=3/5
cosx=√(1-sin²x)=√(1-9/25)=√16/25=4/5
sin2x=2sinx*cosx=2*3/5*4/5=24/25
cos2x=cos²x-sin²x=16/25-9/25=7/25
tg2x=sin2x/cos2x=24/25:7/25=24/25*25/7=24/7