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c) [tex]2log_2(-x)=1+log_2(x+4)[/tex]
d) [tex]log_2(x+3)\ \textgreater \ 3[/tex]
e) [tex]log \frac{1}{3}(x+1)-log \frac{1}{3}(3-x)\ \textgreater \ 0 [/tex]
c) [tex]2log_2(-x)=1+log_2(x+4)[/tex]
d) [tex]log_2(x+3)\ \textgreater \ 3[/tex]
e) [tex]log \frac{1}{3}(x+1)-log \frac{1}{3}(3-x)\ \textgreater \ 0 [/tex]
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Всё обязательно решаем на ОДЗ.