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Saires777
@Saires777
July 2022
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Помогите пожалуйста!!!!!!!
а) [tex] \left \{ {{12-3x^2\ \textless \ 0} \atop {-x^2+x-6\ \textless \ 0}} \right. [/tex]
б) [tex] \left \{ {{1-2x\ \textgreater \ 5} \atop {5x+2\ \textgreater \ x-2}} \right. [/tex]
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sedinalana
Verified answer
1
12-3x²<0
3(x-2)(x+2)>0
x=2 x=-2
x<-2 U x>2
-x²+x-6<0
x²-x+6>0
D=1-24=-23<0⇒x∈R
Ответ x∈(-∞;-2) U (2;∞)
2
1-2x>5
-2x>4
x<-2
2x+2>x-2
2x-x>-2-2
x>-4
Ответ x∈(-4;-2)
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Answers & Comments
Verified answer
112-3x²<0
3(x-2)(x+2)>0
x=2 x=-2
x<-2 U x>2
-x²+x-6<0
x²-x+6>0
D=1-24=-23<0⇒x∈R
Ответ x∈(-∞;-2) U (2;∞)
2
1-2x>5
-2x>4
x<-2
2x+2>x-2
2x-x>-2-2
x>-4
Ответ x∈(-4;-2)