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RQMU
@RQMU
July 2022
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Вычислите площадь фигуры, ограниченной линиями [tex] y=-x^2+9 [/tex] , [tex] y=0 [/tex] .
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1233090
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Решение задания смотри на фотографии
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1233090
пожалуйста
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-x^2+9=0
-x^2=-9
x^2=9
x1=3
x2=-3
(-3;3) ∫ (-x^2+9) dx = -x^3/3+9x | (-3;3) = -3^3/3+9*3 -(-(-3)^3)/3 +9*(-3) ) =
=-9+27-9+27=-18+54=36
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Verified answer
Решение задания смотри на фотографииVerified answer
-x^2+9=0-x^2=-9
x^2=9
x1=3
x2=-3
(-3;3) ∫ (-x^2+9) dx = -x^3/3+9x | (-3;3) = -3^3/3+9*3 -(-(-3)^3)/3 +9*(-3) ) =
=-9+27-9+27=-18+54=36