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guvirmaxim1
@guvirmaxim1
July 2022
1
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[tex] \left \{ {{log_{2}( x+14)+log_{2}(x+y)=6 } \atop {log_{4}(x+y)=0 }} \right. [/tex]
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Checov7400
Log2(х+14)(х+у)=6Log2(2) Log4(x+y)=0
(x+14)(x+y)=2^6 (1) (x+y)=4^0
x+y=1 (2)
подставим (2) в (1) ⇒ (х+14)*1=2^6 ⇒ x+14=64 ⇒ x=50
найдем у из (2) уравнения 50+у=1 у=-49
Ответ: х=50; у=-49
2 votes
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Answers & Comments
(x+14)(x+y)=2^6 (1) (x+y)=4^0
x+y=1 (2)
подставим (2) в (1) ⇒ (х+14)*1=2^6 ⇒ x+14=64 ⇒ x=50
найдем у из (2) уравнения 50+у=1 у=-49
Ответ: х=50; у=-49