Вычислить [tex] 8^{log_{2}5-log_{27}3 } [/tex]. Created by valterkazan. algebra-ru

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[tex] 8^{log_{2}5-log_{27}3 } [/tex]

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Nananey2000 $8^{log_{2}5-log_{27}3 } = 2^{3(log_{2}5-log_{27}3 ) } =2^{3log_{2}5-log_{3}3 }=2^{log_{2}5^3-log_{3}3 }= \\ =5^3*2^{-1 }= \frac{125}{2} =62.5$

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