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Yuer
@Yuer
June 2022
1
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Решите пожалуйста.
[tex]sin x^{2} [/tex][tex] \frac{x}{2} [/tex]-[tex]cos x^{2} [/tex][tex] \frac{x}{2} [/tex]= [tex] \sqrt{2}/2[/tex]
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tanjt
(sinx/2)^2-(cosx/2)^2=(2^1/2)/2
-cosx=(2^1/2)/2
cosx=-(2^1/2)/2
x=+-arccos(-(2^1/2)/2)+2пк, к -целое число
x=+-3п/4+2пк
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Answers & Comments
-cosx=(2^1/2)/2
cosx=-(2^1/2)/2
x=+-arccos(-(2^1/2)/2)+2пк, к -целое число
x=+-3п/4+2пк