решите неравенства
[tex] \frac{ \sqrt{4 x^{2} +7} }{2x-5} \geq \frac{3}{5-2x} [/tex]
(3x-4)[tex] \sqrt{4x-3} [/tex]≤0
[tex] \frac{16x- x^{3} }{ \sqrt{ x^{2} -16} } \geq 0[/tex]
[tex] \frac{ \sqrt{4 x^{2} +7} }{2x-5} \geq \frac{3}{5-2x} [/tex]
(3x-4)[tex] \sqrt{4x-3} [/tex]≤0
[tex] \frac{16x- x^{3} }{ \sqrt{ x^{2} -16} } \geq 0[/tex]
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(3x-4)√(4x-3)≤0
x≤4/3 x≤3/4
otvet:x=3/4;x∈[3/4;4/3]
3)16x-x³/ √(x²-16)≥0
a)16x-x³≥0⇒x≥0;x≤4;x≤-4
a)√(x²-16)>0⇒x>4;x>-4
b)16x-x³≤0⇒x≤0;x≥4;x≥-4
b)√(x²-16)<0⇒x<4;x<-4
otvet x=4; x∈[0;4);x∈(-4;0]
1)2x-5>0
x>5/2
√(4x²+7) +3≥0
4x²+7≥9
x²≥2/4⇒x≥√2/2;x≥-√2/2
otvet:x∈(-∞;-√2/2] ∨ [√2/2;+∞); x=5/2