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stellaichme
@stellaichme
July 2022
1
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Решить уравнение С ПОМОЩЬЮ ТЕОРЕМЫ ВИЕТА [tex]x^{2}+(\sqrt{2} +\sqrt{6} )x+2\sqrt{3} =0[/tex]
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riaddoktor
х1
+
х2
=
-
(
√
2
+
√
6
)
х1×
х
2
=
2
√
3
х1
=
-
√
2
х2
=
-
√
6
1 votes
Thanks 1
stellaichme
А там знак меняется
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Answers & Comments
х1+х2=-(√2+√6)
х1×х2=2√3
х1=-√2
х2=-√6