tex]Найти вторую производную.пожалуйста...

July 2022 1 9 Report

[tex] -\frac{1}{(1+x)^2} + \frac{20}{3x^3} + \frac{1}{(1-x)^2} [/tex]

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$y=-\frac{1}{(x+1)^2}+\frac{20}{3x^3}+\frac{1}{(1-x)^2}\\
 y= \frac{ 32x^4-40x^2+20}{3x^7-6x^5+3x^3}\\
 y'=\frac{56x^4-32x^6-60x^2+20}{x^{10}-3x^8+3x^6-x^4}\\
 y''=\frac{128x^8-272x^6+480x^4-320x^2+80}{x^{13}-4x^{11}+6x^9-4x^7+x^5}$

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Verified answer

reshite pozhalujsta podrobnoochen srochnopozhalujsta

texvpisat pryamougolnik so storonamiparallelnymi osyam ellipsaploshad kotor

vtoraya cifra shestnadcaterichnogo chetyrehznachnogo chisla ravna pyati pervuyu cifru

osnovanie pozicionnoj sistemy schisleniya x pri kotorom 104h 555u ravnopo

sin x cos x04najti proizvedeniya sin xcos x

texesli mozhno podrobno resheniepotomu chto sama reshila poluchaetsya kakoj to bred

dany tochki abc tak chto abbc35 nuzhno opredelit sootnoshenie abac esli mo

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