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crackosok
@crackosok
August 2022
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[tex] \int\limits^0_{-1} { \sqrt{1-x^{2} } } \, dx = \frac{ \pi}{4} [/tex]
Почему так и каким образом это вычисляется?
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IUV
Verified answer
Integral [-1;0] dx корень(1-x^2) = .....
{x=sin(t);dx=cos(t)dt}
... = integral [3pi/2;2pi] dt cos^2(t) =
= integral [3pi/2;2pi] dt (cos(2t)+1)/2 =
= integral [3pi/2;2pi] dt cos(2t)/2 + integral [3pi/2;2pi] dt 1/2 =
= sin(2t)/4 [3pi/2;2pi] + t/2 [3pi/2;2pi]=
= 0 + pi/4 = pi/4
1 votes
Thanks 1
IUV
исправил некоторые малосущественные ошибки
crackosok
спасибо!
animaldk
===========================================================
2 votes
Thanks 2
crackosok
спасибо!
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Answers & Comments
Verified answer
Integral [-1;0] dx корень(1-x^2) = .....{x=sin(t);dx=cos(t)dt}
... = integral [3pi/2;2pi] dt cos^2(t) =
= integral [3pi/2;2pi] dt (cos(2t)+1)/2 =
= integral [3pi/2;2pi] dt cos(2t)/2 + integral [3pi/2;2pi] dt 1/2 =
= sin(2t)/4 [3pi/2;2pi] + t/2 [3pi/2;2pi]=
= 0 + pi/4 = pi/4
===========================================================