[tex] log_{2}(x) + log_{2}(x - 3) = 2[/tex]помогите пожалуйста. Created by Uliana2404. algebra-ru

tex]помогите пожалуйста...

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[tex] log_{2}(x) + log_{2}(x - 3) = 2[/tex]
помогите пожалуйста

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Sp1keazyYT $log_{2}(x)+log_{2}(x-3)=2 \\ log_{2}(x)+log_{2}(x-3)=2,x// prenadlezit//(3,+\infty) \\ log_{2}(x*(x-3))=2 \\ log_{2}(x^2-3x)=2 \\ x^2-3x=2^2 \\ x^2-3x=4 \\ x^2-3x-4=0 \\ x= \frac{-(-3)+- \sqrt{(-3)^2-4*1*(-4)} }{2*1} \\ x= \frac{3+- \sqrt{9+16} }{2} \\ x= \frac{3+-5}{2} \\ x= \frac{3+5}{2} \\ x= \frac{3-5}{2} \\ x=4 \\ x=-1 =\ \textgreater \ Otvet: x=4$

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