[tex] \sqrt[3]{7- \sqrt{41}} * \sqrt[3]{7+ \sqrt{41}} [/tex]Введите свой вопрос сюда. Created by msmakarovaali. algebra-ru

tex]Введите свой вопрос сюда...

msmakarovaali @msmakarovaali

August 2021 1 35 Report

[tex] \sqrt[3]{7- \sqrt{41}} * \sqrt[3]{7+ \sqrt{41}} [/tex]Введите свой вопрос сюда

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nafanya2014

Verified answer

$\sqrt[3]{7- \sqrt{41} }\cdot \sqrt[3]{7+ \sqrt{41} }=\sqrt[3]{(7- \sqrt{41})(7+ \sqrt{41}) }=\sqrt[3]{(7) ^{2} - (\sqrt{41}) ^{2} }= \\ = \sqrt[3]{49-41}= \sqrt[3]{8}=2$

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Verified answer

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