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anna063pink
@anna063pink
July 2022
1
13
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Нужно найти одз
[tex] \frac{a}{4x {}^{2} + 25} [/tex]
x не равно:
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OralB666
4x^2+25≠0
x^2≠-25/4
x∈R
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Answers & Comments
4x^2+25≠0
x^2≠-25/4
x∈R