Упростите на ОДЗ:
[х- 3/(х-1)] * [2*(1-х)/(6+2х-2х²)] = [(х*(х-1)-3)/(х-1)] * [2*(х-1)/(2х²-2х-6)]=
= [(х²-х-3)/(х-1)] * [2*(x-1)/2*([x²-x-3)] = 1
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Answers & Comments
[х- 3/(х-1)] * [2*(1-х)/(6+2х-2х²)] = [(х*(х-1)-3)/(х-1)] * [2*(х-1)/(2х²-2х-6)]=
= [(х²-х-3)/(х-1)] * [2*(x-1)/2*([x²-x-3)] = 1