вычислите в градусах arccos(-sin2009°)
2009=360*5+209=360*5+270-61
-sin2009=-sin(360*5+270-61)=-sin(270-61)=сos61
arccos(-sin2009°)=arccos(сos61)=61
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2009=360*5+209=360*5+270-61
-sin2009=-sin(360*5+270-61)=-sin(270-61)=сos61
arccos(-sin2009°)=arccos(сos61)=61