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katusha312k
@katusha312k
June 2022
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(x-2)^4+(x-2)^2-2=0 .Решите уравнение
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Banabanana
Verified answer
(x-2)⁴+(x-2)²
-2=0
Замена:
(х-2)² = t; t>0
t²+t-2=0
D=1²-4*1*(-2)=1+8=9=3²
t₁=(-1-3)/2=-2 -∅
t₂=(-1+3)/2=1
Обратная замена:
(x-2)²=1
x-2=1 или х-2=-1
х=1+2 х=-1+2
х=3 х=1
Ответ: х=1; х=3
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Answers & Comments
Verified answer
(x-2)⁴+(x-2)²-2=0Замена:
(х-2)² = t; t>0
t²+t-2=0
D=1²-4*1*(-2)=1+8=9=3²
t₁=(-1-3)/2=-2 -∅
t₂=(-1+3)/2=1
Обратная замена:
(x-2)²=1
x-2=1 или х-2=-1
х=1+2 х=-1+2
х=3 х=1
Ответ: х=1; х=3