|(x-6)^3+28|=36 найти корни. Created by aurum991. matematika-ru

|(x-6)^3+28|=36 найти корни...

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|(x-6)^3+28|=36
1. (x-6)^3+28=36
(x-6)^3=8
(x-6)^3=2^3
x-6=2
x=8
2. (x-6)^3+28=-36
(x-6)^3=-64
(x-6)^3=(-4)^3
x-6=-4
x=2
Ответ 2 8

1 votes Thanks 2

sedinalana |x|=a⇒
[x=-a
[x=a
(x-6)³+28=-36 U (x-6)³+28=36
(x-6)³=-28-36 U (x-6)³=-28+36
(x-6)³=-64 U (x-6)³=8
x-6=∛-64 U x-6=∛8
x-6=-4 U x-6=2
x=6-4 U x=6+2
x=2 U x=8
Ответ x=2,x=8

1 votes Thanks 1

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