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anya1209
@anya1209
July 2022
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(x+1) (x+2)(x-2)(x-3)=10 Найти действительные корни уравнения
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Mariian
(Х+1)(х+2)(х-2)(х-3)=10
(Х^2+2х+х+2)(х^2-3х-2х+6)=10
(Х^2+3х+2)(х^2-5х+6)=10
Х^4-5х^3+6х+3х^3-15х^2+18х+2х^2-10х+12=10
Х^4-2х^3+14х-13х^2+12=10
Х^4-2х^3+14х-13х^2=-2
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Answers & Comments
(Х^2+2х+х+2)(х^2-3х-2х+6)=10
(Х^2+3х+2)(х^2-5х+6)=10
Х^4-5х^3+6х+3х^3-15х^2+18х+2х^2-10х+12=10
Х^4-2х^3+14х-13х^2+12=10
Х^4-2х^3+14х-13х^2=-2