x^2-3x-4)

December 2021 1 6 Report

(X+3/x-4)+(1/x^2-3x-4)<или равно 0

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(x+3)/(x-4)+1/(x+1)(x-4)≤0
(x²+x+3x+3+1)/(x+1)(x-4)≤0
(x²+4x+4)/(x+1)(x-4)≤0
(x+2)²/(x+1)(x-4)≤0
x=-2 x=-1 x=4
+ + _ +
------------[-2]------------(-1)-------------(4)-----------------
x∈(-1;4) U {-2}

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