(y^2-5) (y^2+5) (2a-3) ^2-(a-4) (4+a) 25m^2-10mn^3+n^6 Дам 100 баллов.. Created by aminarustam233. algebra-ru

(y^2-5) (y^2+5) (2a-3) ^2-(a-4) (4+a) 25m^2-10mn^3+n^6 Дам 100 баллов...

aminarustam233 @aminarustam233

December 2021 1 7 Report

(y^2-5) (y^2+5) (2a-3) ^2-(a-4) (4+a) 25m^2-10mn^3+n^6 Дам 100 баллов.

Answers & Comments

sangers1959

Verified answer

Объяснение:

$(y^2-5)(y^2+5)=y^4-25.\\\\(2a-3)^2-(a-4)(4+a)=4a^2-12a+9-(a-4)(a+4)=\\=4a^2-12a+9-(a^2-16)=4a^2-12a+9-a^2+16=3a^2-12a+25.\\\\25m^2-10mn^3+n^6=(5m)^2-2-5m*n^3+(n^3)^2=(5m-n^3)^2.$

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