Verified answer

1/log(2)x -1=4*1/2*log(2)x

1-log(2)x=2log^2(2)x                     x>0  x/=1

пусть LOG(2)x=t

2t^2+t-1=0

D=1+8=9

t1=(-1-3)/4=-1   log(2)x=-1   x=1/2

t2=1/2                 log(2)x=1/2     x=V2

Verified answer

log(x)2-1=4log(2)√x;

log(x)2-1=2log(2)x;

log(2)x=t;

1/t-1=2t;

2t²+t-1=0;

t²+(1/2)t-(1/2)=0;

t₁=-1;

t₂=1/2;

log(2)x=-1; x₁=1/2;

log(2)x=1/2; x₂=√2.

Ответ: 1/2, √2.