MuhammadGulu

[tex] {(16 {x}^{2} + 1)}^{2} - {64x}^{2} = {(4x + 1)}^{2} {(4x - 1)}^{2} [/tex]

[tex] {m}^{2} + mn - m - am - an + a = (m - n)(m + a - 1)[/tex]

[tex]3a + 15 = 3(a + 5)[/tex]