Решите систему уравнений: 6^(1+log6(x+y))=48 log8(x+y)+log8(x-y)=4/3 Help me!!!!. Created by Jado134679. algebra-ru

3 Help me!!!!...

July 2022 2 11 Report

Решите систему уравнений:
6^(1+log6(x+y))=48
log8(x+y)+log8(x-y)=4/3

Help me!!!!

sedinalana 6^(1+log6(x+y))=48⇒6*6^(log(6)(x+y)=48⇒6*(x+y)=48⇒x+y=8
log8(x+y)+log8(x-y)=4/3⇒log(8)[(x+y)(x-y)]=4/3⇒(x+y)(x-y)=16⇒x-y=2
прибавим
2x=10
x=5
5=y=8
y=3
(5;3)

Answers & Comments

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