Решите систему уравнений:
6^(1+log6(x+y))=48
log8(x+y)+log8(x-y)=4/3
Help me!!!!
6^(1+log6(x+y))=48
log8(x+y)+log8(x-y)=4/3
Help me!!!!
More Questions From This User See All
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
log8(x+y)+log8(x-y)=4/3⇒log(8)[(x+y)(x-y)]=4/3⇒(x+y)(x-y)=16⇒x-y=2
прибавим
2x=10
x=5
5=y=8
y=3
(5;3)