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Jado134679
@Jado134679
July 2022
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Решите неравенство
(1/log5(3-2x))+(1/4+log5(3-2x))<0
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sedinalana
ОДЗ
3-2x>0
2x<3
x<1,5
x∈(-∞;1,5)
log(5)(3-2x=t
1/t+1/(4+t)<0
(4+t+t)/t(4+t)<0
2(t+2)/t(t+4)<0
t=-2 t=0 t=-4
_ + _ +
--------(-4)------------(-2)-----------(0)-----------(1,5)---------
//////////////////////////////////////////////////////////////////////
x∈(-∞;-4) U (-2;0)
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Answers & Comments
3-2x>0
2x<3
x<1,5
x∈(-∞;1,5)
log(5)(3-2x=t
1/t+1/(4+t)<0
(4+t+t)/t(4+t)<0
2(t+2)/t(t+4)<0
t=-2 t=0 t=-4
_ + _ +
--------(-4)------------(-2)-----------(0)-----------(1,5)---------
//////////////////////////////////////////////////////////////////////
x∈(-∞;-4) U (-2;0)