дана геометрическая прогрессия b1=1/6 b2=1/3 найти 6 член этой прогрессии
q=b2/b1=1/3 : 1/6 = 1/3 * 6/1 = 2
b6 = b1*q^5 = 1/6 * 2^5 = 1/6 * 32 = 32/6 = 16/3 = 5ц1/3
q=b2/b1=1/3*6=2 => b6=b1*q^5=1/6*32=5,3=5ц1/3
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q=b2/b1=1/3 : 1/6 = 1/3 * 6/1 = 2
b6 = b1*q^5 = 1/6 * 2^5 = 1/6 * 32 = 32/6 = 16/3 = 5ц1/3
q=b2/b1=1/3*6=2 => b6=b1*q^5=1/6*32=5,3=5ц1/3