Объяснение:
1)
[tex]f(x)=x^4+2x^3-3x+1.\\\\f'(x)=(x^4+2x^3-3x+1)'=4x^3+2*3x^2-3=4x^3+6x^2-3.\\\\f''(x)=(4x^3+6x^2-3)'=3*4x^2+2*6x=12x^2+12x.[/tex]
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Answers & Comments
Объяснение:
1)
[tex]f(x)=x^4+2x^3-3x+1.\\\\f'(x)=(x^4+2x^3-3x+1)'=4x^3+2*3x^2-3=4x^3+6x^2-3.\\\\f''(x)=(4x^3+6x^2-3)'=3*4x^2+2*6x=12x^2+12x.[/tex]