y'=1/(2√x)+8x
y'=1/(2√9)+8*9=72 [tex]\frac{1}{6}[/tex]
(√x)'=1/(2√x)
(xⁿ)'=n*xⁿ⁻¹
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y'=1/(2√x)+8x
y'=1/(2√9)+8*9=72 [tex]\frac{1}{6}[/tex]
(√x)'=1/(2√x)
(xⁿ)'=n*xⁿ⁻¹