(1-сos4x)/2+(1+cos2x)/2=1
1-сos4[+1+cos2x=2
os2x-cos4x=0
2sin3x*sin2x=0
sin3x=0
3x=πn; n∈Z
x=πn/3 n∈Z;
sin2x=0
2x=πn; n∈Z
x=πn/2 n∈Z;
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(1-сos4x)/2+(1+cos2x)/2=1
1-сos4[+1+cos2x=2
os2x-cos4x=0
2sin3x*sin2x=0
sin3x=0
3x=πn; n∈Z
x=πn/3 n∈Z;
sin2x=0
2x=πn; n∈Z
x=πn/2 n∈Z;