Ответ:
5
Объяснение:
f (x) = y^2 - 12y + 41
f ` (x) = (y^2 - 12y + 41) ` = 2y - 12
f ` (x) = 0
2y - 12 = 0
2y = 12
y = 6
f (6) = 6^2 - 12 × 6 + 41 = 36 - 72 + 41 = 5
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Ответ:
5
Объяснение:
f (x) = y^2 - 12y + 41
f ` (x) = (y^2 - 12y + 41) ` = 2y - 12
f ` (x) = 0
2y - 12 = 0
2y = 12
y = 6
f (6) = 6^2 - 12 × 6 + 41 = 36 - 72 + 41 = 5