1) (3x-1)(3x+1)-(-3x-1)²+5x = 9x²-1-9x²-6x-1+5x =
= -x-2
x = -3 => -(-3)-2=1
2) (x-2)²-(x-2)(x+2)+2(2x-3)+6 =
=x²-4x+4-x²+4+4x-6+6 = 8
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Answers & Comments
1) (3x-1)(3x+1)-(-3x-1)²+5x = 9x²-1-9x²-6x-1+5x =
= -x-2
x = -3 => -(-3)-2=1
2) (x-2)²-(x-2)(x+2)+2(2x-3)+6 =
=x²-4x+4-x²+4+4x-6+6 = 8