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Ответ:

[tex] \frac{( 6 - 2i)(3 + 2i)}{2i - 1} = \\ = \frac{18 + 12i - 6i + 4}{2i - 1} = \\ = \frac{2(11 + 3i)}{2i - 1} \times \frac{2i + 1}{2i + 1} = \\ = \frac{2 \times 5(5i + 1)}{ - 5} = \\ = - 2(5i + 1)[/tex]