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dubininaaliaksandra
@dubininaaliaksandra
May 2023
1
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помогите решить задачу по геометрии про окружность
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zmeura1204
Ответ:
x=32
Решение:
С1=2πR;
R=C1/2π=40π/2π=20 (AO)
C2=2πr;
r=C2/2π=24π/2π=12 (HO)
∆AHO- прямоугольный треугольник
По теореме Пифагора
АН=√(R²-r²)=√(20²-12²)=√(400-144)=
=√256=16
x=2*AH=2*16=32
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Answers & Comments
x=32
Решение:
С1=2πR;
R=C1/2π=40π/2π=20 (AO)
C2=2πr;
r=C2/2π=24π/2π=12 (HO)
∆AHO- прямоугольный треугольник
По теореме Пифагора
АН=√(R²-r²)=√(20²-12²)=√(400-144)=
=√256=16
x=2*AH=2*16=32