Ответ:

x є (14/5 ; 13/3]

Объяснение:

[tex]\left \{ {{8-2x < 3x - 6} \atop {12-x+1 \geq 2x}} \right. \\\left \{ {{-5x < -14} \atop {-3x \geq -13}} \right. \\\left \{ {{5x > 14} \atop {3x \leq 13}} \right. \\\left \{ {{x > \frac{14}{5} } \atop {x \leq \frac{13}{3} }} \right. \\\\x (14/5; 13/3][/tex]