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pororoplol
@pororoplol
March 2022
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решить интеграл используя метод подведения под знак дифференциала
∫((2х)/(х²-7))dx
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sedinalana
Verified answer
T=x²-7
dt=2xdx
S[2xdx/(x²-7)=Sdt/t=lnt=ln(x²-7)+C
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Answers & Comments
Verified answer
T=x²-7dt=2xdx
S[2xdx/(x²-7)=Sdt/t=lnt=ln(x²-7)+C