lg5 + lg(x+10) = 1 + lg(21x-20) - lg(2x-1)
решитеее:*
5x+50=(210x-200)/(2x-1)
(5x+50)(2x-1)=210x-200
10x^2+95x-50-210x-200=0
10x^2-115x-250=0
2x^2-23-50=0
D=529+400=929
x1=(23+srqt929)/4
x2=(23-srqt929)/4
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Answers & Comments
5x+50=(210x-200)/(2x-1)
(5x+50)(2x-1)=210x-200
10x^2+95x-50-210x-200=0
10x^2-115x-250=0
2x^2-23-50=0
D=529+400=929
x1=(23+srqt929)/4
x2=(23-srqt929)/4