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cmdalt
@cmdalt
August 2022
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Найдите функцию, обратную к функции y=(x-8)^-1
Указать её Область Определения и множество значений
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MizoriesKun
Verified answer
y=(x-8)^-1
y=1/(x-8)
х=1/(у-8
)
⇒ у=(1/х) +8 ОДЗ х≠0 х∈(-∞;0)∪(0;+∞) у∈(-∞;8)∪(8;+∞)
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Answers & Comments
Verified answer
y=(x-8)^-1y=1/(x-8)
х=1/(у-8) ⇒ у=(1/х) +8 ОДЗ х≠0 х∈(-∞;0)∪(0;+∞) у∈(-∞;8)∪(8;+∞)