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cmdalt
@cmdalt
July 2022
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Помогите с решение пожлуйста.[tex] \sqrt{x^2-4x} \ \textgreater \ x-3[/tex]
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MizoriesKun
√(х²-4х) > x-3 ОДЗ х²-4х²>0 x*(x-4)>0 x>0 , x> 4
(√(х²-4х))² > (x-3)²
(х²-4х) > x²-6x+9
х²-4х-х²+6х > 9
2x > 9
x>4,5
x∈(4,5; +∞)
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Answers & Comments
(√(х²-4х))² > (x-3)²
(х²-4х) > x²-6x+9
х²-4х-х²+6х > 9
2x > 9
x>4,5
x∈(4,5; +∞)