номер 4 решите плз срочно. Created by Vanek011. algebra-ru

4.2) ОДЗ: 2x+3>0 2x>-3 x> -1.52x+3≤ (1/5)⁻³2x+3≤5³2x≤125-32x≤122x≤61{x> -1.5{x≤61x∈(-1.5; 61]3) ОДЗ: x≠ -2(11x²-x)(2+x)≤011x(x- ¹/₁₁)(x+2)≤0x(x - ¹/₁₁)(x+2)≤0x=0 x=¹/₁₁ x= -2 - + - +-------- -2 ------------- 0 ------------- ¹/₁₁ ------------\\\\\\\\\\ \\\\\\\\\\\\\\\\x∈(-∞; -2)U[0; ¹/₁₁]Новые вопросы в Алгебра13) (x+4)²(x²+14x+49)/x+5>0;14)2x+3/3-x > x+2/x-3Мають вийти такі відповіді:⬇️⬇️на другому фото(sin (2π-x) tg( 3π/2-x) -cos(x-π)-sin (x-π))2 + cos2(π-x)В десятичний дрібПомогите решить задачурешите уравнениепомогите1. Розв'язати нерівність . 1/x² - 3x + 2 <= 1/2 У відповідь записати добуток усіх цілих чисел, які не є розв'язками нерівності.2. Розв'язати нерів…ність. x - 8/x² - 5x + 4 > 2/x + 1. У відповідь записати найменший додатний цілий розв'язок3. Розв'язати нерівність . 2 + 1/x - 3 + x - 3/x + 2)<= 1/(x - 3)(x + 2). У відповідь записати найбільший цiлий розв'язокЯкий спільний множник можна винести за дужки?36z−66 =(6z−11)Периметр трапеции 68 а площа вписанного в неё круга 225 n см ^2_ Найти площу трапецииСума перших трьох чисел, що утворюють зростаючу арифметичну прогресію, дорівнює 2, а сума квадратів цих трьох чисел дорівнює 14/9. Знайти третій член…прогресії.Сума трьох чисел, що утворюють арифметичну прогресію, до рiвнює 111. Друге число більше від першого в 5 разів. Знайти перше число. Треба щоб весь розв…'язок повністю розписали!!!Властивості прямокутника ромба, квадрата.ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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\u0437\u0430\u043f\u0438\u0441\u0430\u0442\u0438 \u0434\u043e\u0431\u0443\u0442\u043e\u043a \u0443\u0441\u0456\u0445 \u0446\u0456\u043b\u0438\u0445 \u0447\u0438\u0441\u0435\u043b, \u044f\u043a\u0456 \u043d\u0435 \u0454 \u0440\u043e\u0437\u0432'\u044f\u0437\u043a\u0430\u043c\u0438 \u043d\u0435\u0440\u0456\u0432\u043d\u043e\u0441\u0442\u0456.\n2. \u0420\u043e\u0437\u0432'\u044f\u0437\u0430\u0442\u0438 \u043d\u0435\u0440\u0456\u0432\u043d\u0456\u0441\u0442\u044c. x - 8\/x\u00b2 - 5x + 4 > 2\/x + 1. \u0423 \u0432\u0456\u0434\u043f\u043e\u0432\u0456\u0434\u044c \u0437\u0430\u043f\u0438\u0441\u0430\u0442\u0438 \u043d\u0430\u0439\u043c\u0435\u043d\u0448\u0438\u0439 \u0434\u043e\u0434\u0430\u0442\u043d\u0438\u0439 \u0446\u0456\u043b\u0438\u0439 \u0440\u043e\u0437\u0432'\u044f\u0437\u043e\u043a\n3. \u0420\u043e\u0437\u0432'\u044f\u0437\u0430\u0442\u0438 \u043d\u0435\u0440\u0456\u0432\u043d\u0456\u0441\u0442\u044c . 2 + 1\/x - 3 + x - 3\/x + 2)<= 1\/(x - 3)(x + 2). \u0423 \u0432\u0456\u0434\u043f\u043e\u0432\u0456\u0434\u044c \u0437\u0430\u043f\u0438\u0441\u0430\u0442\u0438 \u043d\u0430\u0439\u0431\u0456\u043b\u044c\u0448\u0438\u0439 \u0446i\u043b\u0438\u0439 \u0440\u043e\u0437\u0432'\u044f\u0437\u043e\u043a"},{"id":49776855,"content":"\u042f\u043a\u0438\u0439 \u0441\u043f\u0456\u043b\u044c\u043d\u0438\u0439 \u043c\u043d\u043e\u0436\u043d\u0438\u043a \u043c\u043e\u0436\u043d\u0430 \u0432\u0438\u043d\u0435\u0441\u0442\u0438 \u0437\u0430 \u0434\u0443\u0436\u043a\u0438?\n36z\u221266 = \n(6z\u221211)"},{"id":49776729,"content":"\u041f\u0435\u0440\u0438\u043c\u0435\u0442\u0440 \u0442\u0440\u0430\u043f\u0435\u0446\u0438\u0438 68 \u0430 \u043f\u043b\u043e\u0449\u0430 \u0432\u043f\u0438\u0441\u0430\u043d\u043d\u043e\u0433\u043e \u0432 \u043d\u0435\u0451 \u043a\u0440\u0443\u0433\u0430 225 n \u0441\u043c ^2_ \u041d\u0430\u0439\u0442\u0438 \u043f\u043b\u043e\u0449\u0443 \u0442\u0440\u0430\u043f\u0435\u0446\u0438\u0438"},{"id":49776717,"content":"\u0421\u0443\u043c\u0430 \u043f\u0435\u0440\u0448\u0438\u0445 \u0442\u0440\u044c\u043e\u0445 \u0447\u0438\u0441\u0435\u043b, \u0449\u043e \u0443\u0442\u0432\u043e\u0440\u044e\u044e\u0442\u044c \u0437\u0440\u043e\u0441\u0442\u0430\u044e\u0447\u0443 \u0430\u0440\u0438\u0444\u043c\u0435\u0442\u0438\u0447\u043d\u0443 \u043f\u0440\u043e\u0433\u0440\u0435\u0441\u0456\u044e, \u0434\u043e\u0440\u0456\u0432\u043d\u044e\u0454 2, \u0430 \u0441\u0443\u043c\u0430 \u043a\u0432\u0430\u0434\u0440\u0430\u0442\u0456\u0432 \u0446\u0438\u0445 \u0442\u0440\u044c\u043e\u0445 \u0447\u0438\u0441\u0435\u043b \u0434\u043e\u0440\u0456\u0432\u043d\u044e\u0454 14\/9. \u0417\u043d\u0430\u0439\u0442\u0438 \u0442\u0440\u0435\u0442\u0456\u0439 \u0447\u043b\u0435\u043d \u043f\u0440\u043e\u0433\u0440\u0435\u0441\u0456\u0457."},{"id":49776709,"content":"\u0421\u0443\u043c\u0430 \u0442\u0440\u044c\u043e\u0445 \u0447\u0438\u0441\u0435\u043b, \u0449\u043e \u0443\u0442\u0432\u043e\u0440\u044e\u044e\u0442\u044c \u0430\u0440\u0438\u0444\u043c\u0435\u0442\u0438\u0447\u043d\u0443 \u043f\u0440\u043e\u0433\u0440\u0435\u0441\u0456\u044e, \u0434\u043e \u0440i\u0432\u043d\u044e\u0454 111. \u0414\u0440\u0443\u0433\u0435 \u0447\u0438\u0441\u043b\u043e \u0431\u0456\u043b\u044c\u0448\u0435 \u0432\u0456\u0434 \u043f\u0435\u0440\u0448\u043e\u0433\u043e \u0432 5 \u0440\u0430\u0437\u0456\u0432. \u0417\u043d\u0430\u0439\u0442\u0438 \u043f\u0435\u0440\u0448\u0435 \u0447\u0438\u0441\u043b\u043e. \u0422\u0440\u0435\u0431\u0430 \u0449\u043e\u0431 \u0432\u0435\u0441\u044c \u0440\u043e\u0437\u0432'\u044f\u0437\u043e\u043a \u043f\u043e\u0432\u043d\u0456\u0441\u0442\u044e \u0440\u043e\u0437\u043f\u0438\u0441\u0430\u043b\u0438!!!"},{"id":49776708,"content":"\u0412\u043b\u0430\u0441\u0442\u0438\u0432\u043e\u0441\u0442\u0456 \u043f\u0440\u044f\u043c\u043e\u043a\u0443\u0442\u043d\u0438\u043a\u0430 \u0440\u043e\u043c\u0431\u0430, 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номер 4 решите плз срочно...

Vanek011 @Vanek011

July 2022 1 9 Report

номер 4 решите плз срочно

Answers & Comments

m11m

Verified answer

4.
2) ОДЗ: 2x+3>0
2x>-3
x> -1.5

2x+3≤ (1/5)⁻³
2x+3≤5³
2x≤125-3
2x≤122
x≤61

{x> -1.5
{x≤61

x∈(-1.5; 61]

3) ОДЗ: x≠ -2
(11x²-x)(2+x)≤0
11x(x- ¹/₁₁)(x+2)≤0
x(x - ¹/₁₁)(x+2)≤0
x=0 x=¹/₁₁ x= -2
- + - +
-------- -2 ------------- 0 ------------- ¹/₁₁ ------------
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x∈(-∞; -2)U[0; ¹/₁₁]