Ответ:
2Al+3H2SO4=Al2(SO4)3+3H2
1) n(Al)=m/Mr;
n(Al)=2.7/27=0.1
2) 2/0.1=3/x
x=0.1×3/2=0.15 моль(n(H2))
3)V(H2)=n×Vm
V(H2)=0.15×22.4=3.36дм³
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Ответ:
2Al+3H2SO4=Al2(SO4)3+3H2
1) n(Al)=m/Mr;
n(Al)=2.7/27=0.1
2) 2/0.1=3/x
x=0.1×3/2=0.15 моль(n(H2))
3)V(H2)=n×Vm
V(H2)=0.15×22.4=3.36дм³