October 2021 0 4 Report
Помогите есть рисунок и формула!!! Дан треугольник АВС, в котором А С - 5, АВ = 6, ВС= 7. Биссектриса угла С пересекает сторону АВ в точке Б. Определите площадь треугольника АDС. Доп-но=L^2=ab-xy
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